A certain sum of money invested at ci become 1.44 itself in 2 year. If twice their sum were lent at si, how many years will double itself
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Answer:
For CI,
Let sum of money be x and amount is 1.44 times
Therefore,
Amount=P[1+R/100]
(x)(144/100)=(x)[1+R/100]^2
[12/10]^2=[1+R/100]^2
R=20%
For SI,ATQ
Principal=2x and Amount =2×2x=4x and SI=4x-2x=2x
Therefore,
SI=(P×R×T)/100
2x=(2x×20×T)/100
T=5 years
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