Question

A certain sum of money is distributed among 26 people. If each person recives Rs 5.75 and Rs 3.50 is left .what was the initial sum of the money.

Answer 1

See
Each person got 5.75 Rs and there are 26 people. Then total money given is 26×5.75=149.5 RS.
and now add 3.50 Rs as they are left so total sum of money initially was 153Rs.

Answer 2

Answer:

Required initial sum of the money is 153 rupees.

Step-by-step explanation:

Given, a certain sum of money is distributed among 26 people

So total number of persons $= 26$

It is also given that each person recives Rs 5.75.

So, 1 person recives 5.75 rupees

By Unitary method, 26 person recive

$(26 \times 5.75) = 149.5 \: rupees$

It is also given 3.50 rupees is left.

So,the initial sum of money

$= 149.5 + 3.50 \\ =153 \: rupees$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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