Math, asked by anisha4128, 1 year ago

a certain sum of money is invested @ 10% per annum compounded interest the interest compounded annually if the difference between the interest of 3rd year and 1st year is rupees 1105 find the sum invested​

Answers

Answered by Blaezii
7

Answer:

52619.04 rupees

Step-by-step explanation:

Interest rate of 1st year

= 10%

Interest rate of 2nd year =11%

Interest rate of 3rd year =12.1

Interest rate increased by 10% every year

Let the sum is

ATQ

P×12.1/100 -P×10/100 =1105

P(2.1/100 ) =1105

P= 110500/2.1

P=52619.04 rupees

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