A certain sum of money is invested at the rate of 10% per annum compound
Interest, the interest compounded annually. If the difference between the
interests of third year and first year is 1,105, find the sum invested
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interest for 2 years=interest of 3rd year- interest for1st year.
=Rs1105
sum invested=(interest×100)/(time×rate)
=(1105×100)÷(2×10)
=Rs5525
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