A certain sum of money is invested at the rate of 10% per annum compound interest, the interest compounded annually. If the difference between the interests of third year and first year is rs.1105, find the sum invested.
Answers
Answered by
44
the sum invested p is given in the above picture
Attachments:
ARYAanshul:
sorry but the correct answer is 52619.04
jaise tumne solve kiya mai bhi vaise hi krri thi or answer bhi vhi aara tha jo tumhara aaya par answer 5269.04 h
*52619.04
OK main phir se check Karti hoon
ohkk
main ne verification bheja hain shayad ye figure 1105 galat jo
ohkk
Answered by
35
For Annual compound intrest,Amount A at the end of n years is given by
A = where, r is rate of intrest expressed as percentage
Rate of intrest on a amount C =c*r where r is rate of intrest expressed as percentage
Let , the invested amount be P
rate of intrest r=10/100=0.1
Intrest of first year = P * 10/100 = 0.1P
Amount at the end of second year = A2=
Intrest of third year = A2*0.1
Given , difference between intrest of third year and first year is rs.1105
So, 0.1*P* - 0.1P = 1105
0.1P() = 1105
0.1P(0.21) = 1105
P = Rs.52619
Read more on Brainly.in - https://brainly.in/question/1700046#readmore
Similar questions