Math, asked by abhi010, 1 year ago

A certain sum of money is invested at the rate of 10% per annum compound interest, the intrest compounded anually . if the difference between the interest of third year and first year is Rs 1105, find the sum invested

Answers

Answered by alirizvi8860292174

Formula for compound interest,

amount = P(1+r/100) raise to power n

P: principal amount

r: rate if interest

n: no of years

acc to ques,

P(1+10/100) cube - P(1+10/100) =1105

P1(1.1) cube-(1.1))=1105

P(1.313-1.1)=1105

P=1105/0.231=49.78

hope it helps

plz mark as brainliest

abhi010: wrong solution

alirizvi8860292174: Oh.....what's the answer

abhi010: 52619.04

alirizvi8860292174: A = P(1+ 10/100)1 = 1.1P A = P(1.1)2 = 1.21P A = P(1.1)3 = 1.331P So, C.I of ist year = 1.1P – P = 0.1P C.I of 2 year = 1.21P – P = 0.21P So, C.I of 2nd year = 0.21P – 0.1P = 0.11P C.I of 3 year = 1.331P – P = 0.331P C.I of 3rd year= 0.331P – 0.21P = 0.121P So, Difference between C.I of ist and 3rd year = 0.121P – 0.1P = 0.021P 1105 = 0.021P So, P = Rs. 52619.05

alirizvi8860292174: Ab theek h

abhi010: ok

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