Math, asked by chotu1711, 1 year ago

a certain sum of money is put at compound interest compounded half yearly if the interest of for two successive half years and rupees 650 and rupees 760. 50 find the rate of interest​

Answers

Answered by Anonymous
19

Answer:

34%

Step-by-step explanation:

Compound interest for one half-year = Rs. 650

Compound interest for next half year = Rs. 760.50

Time = 2.5 years

So, Compound interest for second half-year = 760.50 - 650 = Rs. 110.50

Interest = 650×0.5×rate/100

= 110.50 = 325×rate/100

= 11050 = 325×rate

= rate = 11050/325

= rate = 34%

Thus, the rate of interest is 34%

Answered by amitnrw
10

Answer:

34 % per annum

Step-by-step explanation:

a certain sum of money is put at compound interest compounded half yearly if the interest of for two successive half years and rupees 650 and rupees 760. 50 find the rate of interest​

Let say Amount = P

Rate of interest = R % per annum

Interest for first half year = P * R * (1/2) / 100 =    PR/200

PR/200 = 650  - eq 1

PR = 130000

Amount after 1st half =  P + PR/200 = P + 650

Interest in 2nd Year = (P + 650) * R * (1/2) /100 = PR/200  + 13R/4

PR/200  + 13R/4 = 760.50  - eq 2

eq 2 - eq 1

13R/4 = 760.50 - 650

=> 13R/4 = 110.5

=> 13R = 442

=> R = 34

Rate of interest = 34 % per annum

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