Math, asked by Talib1128, 1 year ago

A certain sum of money was lent under the following repayment scheme based on Simple Interest: 8% per annum for the initial 2 years 9.5% per annum for the next 4 years 11% per annum for the next 2 years 12% per annum after the first 8 years Find the amount which a sum of ` 9000 taken for 12 years becomes at the end of 12 years

Answers

Answered by bhagyashreechowdhury
18

Answer: Rs. 20,160

Step-by-step explanation:

The formulas  required for solving the given question:

Simple Interest = [P x R x T] / 100 ….. (i)

And,  

Amount = Principal + Simple Interest …. (ii)

We are given that,

Principal sum, P = Rs. 9000

Time, T = 12 years

The sum is lent on a repayment scheme based on simple interest:

8% p.a. for first 2 years

9.5% p.a. for next 4 years

11% p.a. for next 2 years

12% p.a. after 8 years i.e., 12% p.a. was for (12 - 8) = 4 years

Now, based on formula (i), we get

The total interest earned at the end of 12 years will be,

= [(9000*8*2)/100] + [(9000*9.5*4)/100] + [(9000*11*2)/100] + [(9000*12*4)/100]

= [90*8*2] + [90*9.5*4] + [90*11*2] + [90*12*4]

= 1440 + 3420 + 1980 + 4320

= Rs. 11,160

Thus, based on the formula (ii), we get

The amount received at the end of 12 years will be,

= Rs. 9000 + Rs. 11,160  

= Rs. 20,160

Answered by 190amank
0

Answer:

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