Math, asked by BullsEye237, 1 year ago

A certain sum under compound interest, interest being compounded annually earns an interest of Rs. 864 and Rs. 1,036.80 respectively in the third year and fourth year. Find the sum

Answers

Answered by abhi178
8

The sum is 3000 and rate of interest is 20% per annum.

Let the sum of money is P and rate of interest per annum is r.

compound interest of 3rd year = compound interest in 3 years - compound interest in 2 years

= [P(1 + r/100)³ - P] - [P(1 + r/100)² - P]

= P(1 + r/100)²(r/100)

so, P(1 + r/100)²(r/100) = 864 ......(1)

similarly, compound interest of 4th year = P(1 + r/100)³(r/100) = 1036.8 ........(2)

dividing equations (1) and (2) we get,

864/1036.8 = 1/(1 + r/100)

⇒1036.8/864 - 1 = r/100

⇒(1036.8 - 864)/864 = r/100

⇒r = 20%

putting r = 20% in equation (1) we get,

P(1 + 20/100)²(20/100) = 864

⇒P(1 + 1/5)²(1/5) = 864

⇒P(36/25)(1/5) = 864

⇒P = 125 × 864/36 = 125 × 24 = 3000

hence the sum is 3000 Rs.

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