Question

a certain survey revealed that in a town 40% of people read English newspaper while 75% of the people read Vernacular newspaper if 30% of the people read both English and Vernacular newspapers what is the percentage of people who do not read any newspapers​

Answer 1

Step-by-step explanation:

English newspaper readers = 40 percent

Vernacular newspaper readers = 75 percent

total percent = 40 + 75

= 115

common percent = 30 percent

percent of people who read newspaper = 115 - 30

=85 percent

so no. of people who don't read newspaper = 100 - 85

= 15 percent

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Answer 2

Answer:

15% of people do not read any newspaper

Step-by-step explanation:

This problem can be solved based on set theory

No.of people who read english newspaper=40%

$= > n(A) = 40$

No.of people who read Vernacular newspaper=75%

$= > n(B) = 75$

No.of people who read both news papers=30%

$= > n(A∩B) = 30$

From set theory,

No.of people who read newspaper are

$n(AUB) = n(A) + n(B) - n(A∩B) \\ = 40 + 75 - 30 \\ = 85$

Therefore,percentage of people who do not read and newspaper is

$u = 100 - n(AUB) = 100 - 85 \\ = 15$

15% of people do not read any newspaper

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