Question

A certain temperature at total pressure of 10 is 256 5 pascal iodine vapour contains 40% by volume of iodine atoms to gas gives to i gas calculate the kp for the equilibrium

Answer 1

Answer:

Explanation:

It is given that total pressure (PT)is 10^5\ Pa and partial pressure of I atom = 40 % of PT

So, the partial pressure of I atom = \frac{40}{100}\times 10^5 = 4\times 10^4Pascal

The partial pressure of I_2 = 60% of PT

So, the partial pressure of I_2 = \frac{60}{100}\times 10^5=6\times 10^4Pascal

Now, for the reaction  I_{(g)}\rightleftharpoons 2I_{(g)}

K_p = \frac{(p_I)^2}{p_{I_2}} = \frac{(4\times 10^4)^2}{6\times 10^4}\ Pa

                          =2.67\times 10^4\ Pa