a certain transverse sinusoidal wave of wavelength 40 cm is moving to the right transverse acceleration of the particle at X = 0 as a function of time is shown in figure the shape of the wave between X = 0 and X = 40 cm per second is
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Answer:
λ=20cm,T=4s
From the figureV
max =5cm/s=Aω
A= ω5
A= 2π/T
5 = 2π5×4
[A= π10 cm]
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Answered by
1
ANSWER
λ=20cm,T=4s
From the figure
V
max
=5cm/s=Aω
=A= ω5
A= 2π/T5
A = π 5×4
A= π20 cm.
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