A certain virus infects one in every 400 people. a test used to detect the virus in a person is positive 90% of the time if the person has the virus and 10% of the time if the person does not have the virus. let a be the event "the person is infected" and b be the event "the person tests positive." (a) find the probability that a person has the virus given that they have tested positive. (b) find the probability that a person does not have the virus given that they have tested negative.
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90% of 100% = 9/10
Answer to part A is 9/10.
10% of 100% = 1/10
Answer to part B is 1/10
CHECK
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90% of 400 = 360 infected people
360/400 = 9/10
Every 9 of 10 people are infected.
10% of 400 = 40 infected people
40/400 = 1/10
Every 1 of 10 people are not infected.
Answer to part A is 9/10.
10% of 100% = 1/10
Answer to part B is 1/10
CHECK
-----
90% of 400 = 360 infected people
360/400 = 9/10
Every 9 of 10 people are infected.
10% of 400 = 40 infected people
40/400 = 1/10
Every 1 of 10 people are not infected.
Rishab11111111:
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The answer for this question is every 1 of 10 is not infected. Please mark as brilliant.
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