Question

A certain volume of a gas is kept at a pressure of 10 atm. When the pressure
is decreased to 8 atm, the gas occupies a volume of 700 L. What was
the initial volume of the gas assuming temperature remains constant?

Answer 1

Answer:

560 lts.

Explanation:

As per Boyle's law, pressure(P) of a given quantity of gas varies inversely with its volume(V) at constant temperature i.e., PV = constant

Let the initial volume of the gas be V1.

Given:

Initial pressure, P1 = 10 atm.

Final pressure, P2 = 8 atm,

Final volume, V2 = 700 L

So as per Boyle's law, P1. V1 = P2. V2

=> V1 = P2. V2 / P1 = 8 x 700 / 10 = 560

So the initial volume is 560 lt.