A certain weak acid has ka = 1 * 10-4. Calculate the equilibrium constant for its reaction with strong base
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Explanation:
Solution
Equilibrium reaction is
HA+BOH⇌BA+H2O
weak strong
HA+B++OH−⇌B++A−+H2O
or HA+OH−⇌A−+H2O
K=[HA][OH−][A−]
In the above reaction
Kh=[A−][HA][OH−]
so, K=Kh1
We know that
Kh=KaKw=1.0×10−410−14=10−10
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