Question

a certan air capacitor has a capacitance of 20 uf if a dielectric having relative permittivity of 5 is introduced between the plates the value of capacitance would be​

Answer 1

Answer:

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Step-by-step explanation:

Step 1: Initial capacitance

Let the initial distance between the plates be d.

Let A be the area of each plate.

Capacitance of the parallel plate capacitor is given by:

C

i

=

d

A∈

0

....(1)

Step 2: Capacitance after inserting dielectric

Let k be the dielectric constant.

C

f

=

d

′

kA∈

0

As the distance between plates is reduced to half, new distance is d

′

=

2

d

∴C

f

=

d

2kA∈

0

=2kC

i

=2×6×8pF=96pF