Question

(a) CFSE for high spin system is zero. Its
electronic distribution is
.​

Answer 1

Answer:

a high spin complex has the potential of having a zero CFSE if the increase in stability resulting from the electrons being placed in the t2g orbitals is cancelled out by the decrease in stability resulting from electrons being placed in the eg orbitals.

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Answer 2

Its electronic distribution is $t^3_{2g}e_g^2$.

• CFSE is the energy difference between $t_{2g}$ and $e_g$.
• The energy contribution for one $t_{2g}$ is -0.4∆o and the energy contribution for $e_{g}$ is +0.6∆o.
• Thus if the energy of the $t_{2g}$ and $e_{g}$ becomes the same then the CFSE will be zero.
• This can be possible for the high spin system if the electronic distribution is $t^3_{2g}e_g^2$. Here the total energy in $t_{2g}$ is 3×(-0.4)=-1.2∆o and total energy in $e_{g}$ is +0.6×2=1.2∆o. Hence CFSE is 0.