Question

A cgarged particle of mass 2 mg hang in air in an electric field of

Answer 1

Answer:

a charged particle of mass 2 mg hang in air in an electric field of strength 4N/C directed upwards. the charge on the particle would be (g=10m/s^-2)

Answer 2

A charged particle of mass 2 mg hang in air in an electric field of strength 4N/C directed upwards. The charge on the particle would be 0.5 x $10^{-5}$C .

(g=10m/s^-2)

Since mass of the particle is 2mg,

• Gravitational force acting downwards will be
• F = mg = 2 x $10^{-6}$   kg x 10m/$s^{2}$ = 2 x $10^{-5}$ N

Given an electric field of strength 4N/C acts upwards.

Force due to electric field is F =  qE , where,

• q is the electric charge and
• E is electric field intensity

Since the particle is in air, these two forces should balance each other.

• Hence mg = qE
• 2 x $10^{-5}$ = q x 4
• Therefore, q  = 0.5 x $10^{-5}$ C