Question

A chain of 125 links is 1.25 m long and has a mass of 2kg with the ends fastened together it is set rotating at 3000rev/min Find the centripetal force on each link -

(1)3.14N
(2)314N
(3)1/3.14N
(4)1/314N


PLZZ EXPLAIN THE ANSWERR​

Answer 1

Explanation:

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Answer 2

Answer:

F = 314.15 N

Explanation:

It is given that,

Number of links, n = 125

Length of the chain, l = 1.25 m

Mass of the chain, m = 2 kg

The mass of each link is, $m=\dfrac{2}{125}=0.016\ kg$

Angular speed, $\omega=3000\ rev/min=314.1593\ rad/s$

Circumference, $C=1.25=2\pi r$

The centripetal force is given by :

$F=m\omega^2 r$

$F=0.016\times 314.1593^2 \times \dfrac{1.25}{2\pi}$

F = 314.15 N

So, the centripetal force acting on each link is 314.15 N. Hence, this is the required solution.