A chain of 5 links, each of mass 0.1 kg, is lifted vertically with a constant acceleradion 1.2ms square. The force of interaction between the top link and the one immediately below it is (a)1.10N b. 0.88 N (c) 0.66n d. 0.44N
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Answer is c) 0.66n plz mark me as brainelist
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