A chain of mass 10 kg and length 10 metre is held vertical by fixing its upper end to a rigid
support. The tension in the chain at a distance 3 metre from the rigid support is
(A) 100 N
(B) 70 N
(C) 143 N
(D) 76 N
A force of 10 N acts on a block The acceleration of the
a = 7 m/s2
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The tension in the chain at a distance 3 metre from the rigid support is 70 N.
Explanation:
Total weight of the chain =10 Kg
Mass per unit length =10/10 Kg per meter
= 1 Kg per meter
Now at a distance of 3 m from the support, the force experienced is due to the remaining chain hanging down i.e. 7 m.
Weight of the chain = 1 Kg/m x 7=7 KG
The force experienced = F =mg
= 7 x 10 = 70 N
Thus the tension in the chain at a distance 3 metre from the rigid support is 70 N.
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