A chain of mass m = 0.80 kg and length l= 1.5 m rests on a rough-surfaced table so that one of its ends hangs over the edge.
Answers
Answered by
2
Area of a quadrilateral ABCD = 1/2 x AC x (Sum of the lengths of the perpendicluars on AC)
Area of the quadrilateral = 325 cm2
Length of one of the perpendicular = 14 cm
Length of AC = 25 cm
Let the length of the other perpendicular be 'x' cm
325 = 25/2 (14 + x)
650 = 25 (14 + x)
14 + x = 26
or x = 12
more
Area of the quadrilateral = 325 cm2
Length of one of the perpendicular = 14 cm
Length of AC = 25 cm
Let the length of the other perpendicular be 'x' cm
325 = 25/2 (14 + x)
650 = 25 (14 + x)
14 + x = 26
or x = 12
more
Similar questions