Question

A chain of mass M and length l if placed on a table and the remaining parts hangs in air. If the coefficient of friction between the table and the chair is mew. Find the maximum length of chain sliding the part of the chain on the table

Answer 1

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A homogeneous chain of length L lies on a table. The coefficient of friction between chain and table is μμ. The maximum length which can hang over the table in equilibrium is ( The vertical portion of table is smooth)

(a)(μμ+1)L(b)(1−μμ)L(c)(1−μ1+μ)L(d)(2μ2μ+1)L(a)(μμ+1)L(b)(1−μμ)L(c)(1−μ1+μ)L(d)(2μ2μ+1)L

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asked Jul 10, 2013 by meena.p 
retagged Jul 10, 2014



1 Answer

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Let 'l' be the desired length hanging out so that the chain is in equilibrium chain starts moving when not pulling force is greater than frictional force.

Let m be the mass of length of chain

gmLgmLl=μmLl=μmL(L−l)g(L−l)g

l=(μμ+1)l=(μμ+1)LL




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Answer 2

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