Question

A chapter has 50 algebra problems. Radha solves some and Sneha solved 4 more problems than Radha. How many problems did each one solves?

Answer 1

$\huge\underline\mathrm\pink{Answer}$

Given:-

Total no. of Problems= 50

Let,

No. of problems solved by radha = x

and, no. of problems solved by Sneha = x+4

According to the question,

➥x+x+4= 50

➥2x+4= 50

➥2x= 50-4

➥2x= 46

➥x= 46/2

➥x= 23

therefore,

Problems solved by radha = 23

And,

Problems solved by Sneha = x+4

= 23+4

= 27

Hope it helps you...!!!!!

Answer 2

Answer:

In a class test containing 10 questions, 5 marks are awarded for every correct answer and (−2) for each wrong and 0 for not attempted questions. We will just forget unattempted questions as it will give her 0 marks

So let us say for any student who gave x right questions and y wrong questions then total marks is given as 5x+(−2)y i.e

5x−2y total marks.

1) Mohan gets 4 correct and 6 incorrect so total score 5×4−2×6 i.e 8marks

2)Reshma gets 5 correct anf 5 incorrect do total marks scored is equal to

5×5−2×5 i.e 15marks

3)Heena gets 2 correct and 5 incorrect. She attempts only 7 questions so for the remaining 3 questions she will score zero marks.

So total marks scored by Heena is 5×2−5×2+0 i.e 0marks

Step-by-step explanation:

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