Question

a chared sphere is connected to a similar uncharged sphere the percentage loss of energy is​

Answer 1

Answer:

Here is your answer buddy

Answer 2

Answer: the percentage loss of energy is​ $50%$%

Explanation:

final charge on each sphere

               = $q_{1}=q_{2}$  $= \frac{q+0}{2}$

                $=\frac{q}{2}$

$U_{3} =\frac{1}{2}\frac{q^{2} }{c}$

$U_{2} =\frac{1}{2}\frac{q_{1} ^{2} }{c}+\frac{1}{2}\frac{q_{2} ^{2} }{c}$

    $=\frac{1}{2c} [\frac{q^{2} }{4} +\frac{q^{2} }{4} ]$

  $=\frac{1}{4} \frac{q^{2} }{c}$

now let's find the difference,Δ$U$

Δ$U$$=(U_{3}-U_{2} )$

    $=\frac{1}{2}( \frac{q^{2} }{c} -\frac{q^{2} }{4c})$

now let's find the percentage loss of energy is​,

% loss = $\frac{dU}{U_{2} } X100$

           $=\frac{q^{2} }{4c} X \frac{2c}{q^{2} } X 100$

          $=\frac{1}{2}X100$

         =50%

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