Question

A charge 5µC is placed at a point. what is work required to carry 1C of charge once round it in circle of 12cm radius ? numerical of physics​

Answer 1

Given:

A charge 5µC is placed at a point. 1C of charge is moved round it in circle of 12cm radius.

To find:

Work done in moving the charge.

Calculation:

Work done is a scalar quantity represented by the scalar product of force and displacement vectors.

Force between the charges will be :

$F = \dfrac{k(q1)(q2)}{ {r}^{2} }$

$= > F = \dfrac{k \times 5 \times {10}^{ - 6} \times 1 }{ {(0.12)}^{2} }$

$= > F = 3.47k \times {10}^{ - 2} \: N$

Now , work done be W

$W = \vec F \: . \: \vec d$

$= > W = F \times d \times \cos( \theta)$

$= > W = F \times d \times \cos( 90 \degree)$

$= > W = F \times d \times 0$

$= > W = 0 \: joule$

So , work done is zero.