A charge 5C rest on the origin another charge of 3mC bring from point A via point B (2, 3, 0) cm. Find the work done to bring the charge.
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Given two points A and B maintained at same potential i.e, 6V. We have to calculate the work done to move a charge %C between A and B.
Since work done to move 5C between two points A and B= change in potential at two points × charge
Since change in potential between points A and B is zero, since both the points are maintained at constant potential.
So, the work done is zero.
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