Question

A charge 8.85 µC is placed at the centre of a cube. The electric flux (in SI units) through any one face will be​

Answer 1

Refer to the attachment!!!

Answer 2

Answer:

The electric flux through one face will be 1.6 × $10^5$ $Nm^2C^-1$

Explanation:

Electric flux = $\frac{Charge enclosed}{permittivity in free space}$

Now charge enclosed = total charge inside the cube = 8.85 µC

                                                                                        = 8.85 × $10^-6$C

Permittivity in free space = 8.85 × $10^-12$ $C^2N^-1m^-2$

Electric flux = $\frac{8.85*10^-6}{8.85*10^-12}$ = $10^6$ $Nm^2C^-1$

This is the total electric flux.

In a cube there are 6 surfaces.

So electric flux through one face = $\frac{10^6}{6}$ = 1.6 × $10^5$ $Nm^2C^-1$.