Question

a charge capacitor shares its charge with another capacitor of double capacity. find the total energy of both the capacitor in this situation.​

Answer 1

Answer:

The stored energy in a capacitor is E = (CV^2)/2, where E is the stored energy (in joules or watt-sec), C is the capacitance of the capacitor (in farads), and V is the voltage across the capacitor (in volts). Since the charge stored in in a capacitor is Q = CV, where Q is the stored charge (in coulombs), then V=Q/C, so that E= C [(Q/C]^2]/2 = Q^2/2C. Thus the stored energy E varies with the square of the electric charge Q stored in the capacitor, so if you double the charge Q, the stored energy E in the capacitor will quadruple (i.e., increase by a factor of 4)

Answer 2

Explanation:

Charge Q is given by the relation : Q = CV

Energy is given by the relation: Q * V

C is constant, so if Q doubles, V also has to double, hence energy is quadrupled.