Question

A charge enclosed by the spherical Gaussian surface is 8.85 x 10⁻⁸C. What is the electric flux linked with this surface ? If the radius of sphere is doubled, what is the electric flux ?

Answer 1

Dear Student,

◆ Answer -

Φ = 10^4 Nm^2/C

◆ Explaination -

# Given -

Q = 8.85×10^-8 C

# Solution -

Electric flux passing through Guassian surface is given by -

Φ = Q/ε

Φ = 8.85×10^-8 / 8.85×10^-12

Φ = 10^4 Nm^2/C

Therefore, electric flux passing through spherical surface is 10^4 Nm^2/C.

Hope this helps you...