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A charge is moved in an electric field of a fixed charge distribution from point A to another
B slowly. The work done by external agent in doing so is 100 J. What is the change in poter
energy of the charge as it moves from A to B? What is the work done by the electric fiel
the charge distribution as the charge moves from A to B?
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Answers
Answer:Answer:
Explanation:
Given :-
Work done = 10 joule
Charge = 2 Coulomb
Potential of point A = V(a) = 10 J/2 C = 5 V
Given :-
Work Done = 20 Joule
Charge = 2 coulomb
Potential of Point B = V(b) = 20 J/2 C = 10 V
Solution :-
Potential Difference between Point A and B = V(a) - V(b)
⇒ Potential Difference between Point A and B = 10 V - 5 V
⇒ Potential Difference between Point A and B = 5 V
Now, Work done directly from A to B,
Work Done = Potential Difference × Charge
⇒ Work Done = 5 V × 2 C
⇒ Work Done = 10 Joule
Hence, the potential difference between two points A and B is 5 V and the work done if the same charge is brought directly from A to B is 10 JAnswer:
Explanation:
Given :-
Work done = 10 joule
Charge = 2 Coulomb
Potential of point A = V(a) = 10 J/2 C = 5 V
Given :-
Work Done = 20 Joule
Charge = 2 coulomb
Potential of Point B = V(b) = 20 J/2 C = 10 V
Solution :-
Potential Difference between Point A and B = V(a) - V(b)
⇒ Potential Difference between Point A and B = 10 V - 5 V
⇒ Potential Difference between Point A and B = 5 V
Now, Work done directly from A to B,
Work Done = Potential Difference × Charge
⇒ Work Done = 5 V × 2 C
⇒ Work Done = 10 Joule
Hence, the potential difference between two points A and B is 5 V and the work done if the same charge is brought directly from A to B is 10 J
Explanation:
Answer:
dont't know the answer for this question sorry