A charge is placed at the point of intersection of body diagonals of a cube. The electric flux passing through any one of it's face is
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Answer:
q/6Eo
Explanation:
According to Gaussian theorem the flux passing through a closed surface is
= (Net charge inside the surface)/Eo
Q Charge is placed at the point of intersection of body diagonals of a cube. Thus, total flux is
= q/Eo
Since, the flux will be distributed symmetrically on the faces. Therefore, the flux through one cube will be equal to
= q/6Eo
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