A charge moving in a magnetic field B with velocity v at any angle to the magnetic field the path of charged particle is
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Answer:Here velocity vector have two components
(i) v cos θ, parallel to magnetic field
(ii) v sin θ, perpendicular to magnetic field. Due to component v cos θ, the particle will have a linear motion but due to v sin θ, the particle will have simultaneously a circular motion. The resultant of the two is a helical path.
Explanation:
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