Question

a charge of 1.0C is
place at the top of your college and building and another equal charge at the top of your house take the separation between two charges to be 2.0 km find the force exerted by the charges on each other how many times of your weight is this force

Answer 1

Force exerted = k q1q2/r ^2
= 9×10^9 × 1/4× 1/1000×1/1000
( 1km = 1000 m)

= 2.25×10^3
Electrostatic forces is one of the strongest forces and gravitational force exerted on us by earth is very small compared to it
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Answer 2

Sol.
q base 1 = q base 2 = q = 1.0 C distance between = 2 km = 1 × 10^3 m so, force = kq base 1q base 2/r^2 F = (9 * 10^9) * 1 * 1/(2 * 10^3)^2 = 9 * 10^9/2^2 * 10^6 = 2,25 * 10^3 N The weight of body = mg = 40 * 10 N = 400 N So, wt of body/force between ch arg es = (2.25 * 10^3/4 * 10^2)^-1 = 1/5.6 So, force between charges = 5.6 weight of body.
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