Question

A charge of 1.5C passes through the cross section of a conductor in 4 s. Find the current.
ii) The resistance of the conductor mentioned in (i) is 2.422. Find the potential difference across the
conductor.
Please answer fast ! i will nark it as the brainliest
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Answer 1

Given:-

• Charge=1.5c

• Time=2 seconds

• Resistance=2.422Ω

To find:-

• Magnitude of current

• Potential difference

Concept used:-

• Ohm's law

• Formula for current

Solution:-

We have formula for current:

⇒ I=Q/t

⇒ I=1.5C/4 s

⇒ I=0.375 c/s

⇒ I=0.375 Ampere

Now applying ohm's law to find potential difference:

⇒ V=IR

⇒ V=(0.375 Ampere)×(2.422Ω)

⇒ V=0.908 Ampere.ohm

⇒ V=0.908 volts

Final answers:-

• Current, I=0.375 Ampere

‌• potential difference, v=0.908 volt

Points to remember:-

• Ampere.ohm=volt

• coulomb/second=Ampere

S.I. units:-

• S.I. unit of current is Ampere

• S.I. unit of potential difference is volts

Terminology used:-

• I=current

• Q=charge

• V=potential difference

• t=time

• R=resistance