a charge of 1.6 × 10^-19 C is situated at a distance of 30 cm from another charge of 6.4 × 10^-19C where will be the electric field be zero?
Answers
Answered by
0
center me zero ho jayegi
Answered by
0
Repulsive force of magnitude = 6*10^-3
q1 = 1.6*10^19
q2 = 6.4*10^19
r = 30cm
F = 1/4πε0 * q1*q2/r²
Thus electric field will be zero at the centre.
Similar questions