Question

A charge of 1 columb is placed at rest in the magnetic field of strength 5tesla .How much the force experienced by the charge due to magnetic field?​

Answer 1

Answer:

The force acting on a charged particle moving in a magnetic field

B

is given by

F

=q(

v

×

B

)

⟹

∣

∣

∣

∣

F

∣

∣

∣

∣

=1.6×10

−19

×10

5

×2N

=3.2×10

−14

N