Question

a charge of 1 microcoulomb is kept at a points where the potential is 100 v . the electrical potential energy of the charge will be​

Answer 1

Answer:5×10^-5

Explanation:formula of electrical potential energy is 1/2qv

1/2×10^-6×100=5×10^-5

Answer 2

Answer: The electric potential energy of the charge is 5×10^-5 Joule

Concept: The electrical potential energy of the charge is given by the formula:

E = qv/2

where

E =  electrical potential energy

q = charge

v = potential at the point

Given: charge(q) = 1 microcoulomb = 1 x 10^-6 C

v = 100V

To find: The electric potential energy of the charge

Explanation:

charge(q) = 1 microcoulomb = 1 x 10^-6 C

v = 100V

we have the formula,

E = qv/2

putting values in the formula

E = [(1 x 10^-6)*100]/2

E = 0.5 x 10^-4 J

E = 5 x 10^-5 J

Answer: The electric potential energy of the charge is 5×10^-5 Joule

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