Question

A charge of 10 to the power -10 is placed at the origin the electric field at (1,1) cm due to it ( in N/C)

Answer 1

A charge of 10 to the power -10 is placed at the origin the electric field at (1,1) cm due to it is 0.45 N/C

It has given that a charge of 10^-10 C is placed at the origin, (0,0)

we have to find the electric field at (1,1) cm due to it.

distance between origin to (1,1) , r = √(1 - 0)² + (1 - 0)²} = √2

now electric field at (1,1) due to charge 10^-10 C, E = Kq/r²

= (9 × 10^9 × 10^-10)/(√2)²

= 9/20

= 0.45 N/C

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Answer 2

Answer:

Explanation:

distance between origin to (1,1) , r = √(1 - 0)² + (1 - 0)²} = √2

now electric field at (1,1) due to charge 10^-10 C, E = Kq/r²

= (9 × 10^9 × 10^-10)/(√2)²

= 9/20

= 0.45 N/C