Question

A charge of 10 units is divided so that force between the two charges is maximum when placed 2 cm apart . The two charges are

Answer 1

5and 5

Explanation:

max force directly proportional to (charge)²

since F=kq1q2/d²

so for force to be max (q1q2)² should be maximum

so q1q2² is max for 5and 5

since (q1q2)² for 5 and 5 is 25 where as for other possible cases less than than 25 for example 6and 4 it would be 24