A charge of 10microcoulomb and 4 microcoulomb are located A&B of an equilateral triangle AB&C of side 0.3m.find the total field at point c
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Two point charges +3 nc and -3nc are placed at the corners A and B of an equilateral triangle abc of side 0.3m in air. A charge +2nc is placed at the point C as shown in figure.
magnitude of force between A and C , F = k(3nC)(2nC)/(0.3m)²
= 9 × 10^9 × (3 × 10^-9) × (2 × 10^-9)/0.09
= 10¹¹ × 6 × 10^-18
= 6 × 10^-7 N
and magnitude of force between A and C , F = 6 × 10^-7 N
it is clearly shown that angle between both forces is 120°
now, resultant force = √{F² + F² + 2F²cos120°}
= F = 6 × 10^-7 N
hence, net force acting on it is 6 × 10^-7
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