Question

A charge of 10uc is placed at the origin of x-y coordinate system.the potential difference between two point (o,a) and (a,o) in volt will be

Answer 1

Solution :

n=Iten=Ite

=3.2×10−3×11.6×10−19=3.2×10−3×11.6×10−19

=2×1016

Answer 2

Answer:

The potential difference between  two points is zero.

Explanation:

Given that,

Charge $q = 10\times10^{-6}\ C$

Two points = (0,a),(a,0)

A charge is placed at the origin of x-y coordinates system.

The potential difference on A is

$V_{A}=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{q}{r}$

$V_{A}=\dfrac{10\times10^{-6}\times9\times10^{9}}{a}$

The potential difference on B is

$V_{A}=\dfrac{10\times10^{-6}\times9\times10^{9}}{a}$

The potential difference between  two points is

$V_{AB} = V_{A}-V_{B}$

$V_{AB}= \dfrac{10\times10^{-6}\times9\times10^{9}}{a}-\dfrac{10\times10^{-6}\times9\times10^{9}}{a}$

$V_{AB}=0$

Hence, The potential difference between  two points is zero.