Question

A charge of 10uc is uniformly distributed throughout the volume of a non conducting sphere of radius 2cm calculate the cubicle charge density of the sphere

Answer 1

Answer:

Explanation:

Option 1) Increases as r increases for r<R

Option 2)  Decreases as r increases for O <r<\infty

Option 3) Decreases as  r increases for R <r<\infty

Option 4) both a and c

Uniformly charged Non conducting sphere -

Suppose charge Q is uniformly distributed in the volume of a non conducting sphere of Radius R.

- wherein

For non-conducting solid sphere E_{in}\alpha r

and E_{out}\alpha \frac{1}{r^{2}}

i.e. for r<R; E increases as r increases

and for R<r<¥; E decreases as r increases

 

Option 1)

Increases as r increases for r<R

 

 

 

Option 2)

Decreases as r increases for O <r<\infty

Option 3)

Decreases as  r increases for R <r<\infty

Option 4)

both a and c

Answer 2

Answer:

A total charge of $10*10^{-6} C$ is distributed uniformly throughout a 2cm radius sphere. The  volume charge density is $0.303 C/m^{3}$

Explanation:

• The volume charge density (ρ) is the charge (q) in unit volume (v), that is

        ρ= $q/v$

• For a sphere of radius (r) volume is given by $v=\frac{4}{3} \pi r^{3}$

From the question, we have

the total charge present $q=10*10^{-6}C$

the radius of the sphere $r=2cm=0.02m$

the volume of the sphere $v=\frac{4}{3}* \pi* 0.02^{3}=3.3*10^{-5}m^{3}$

the volume charge density is

ρ= $\frac{10*10^{-6} }{3.3*10^{-5} } =0.303 C/m^{3}$