a charge of 12*10 to the power 5 flows in a conductor for 10 minutes.if the resistance offered by the conductor is 80ohm calculate the
A.current flowing
B.voltate
C.work
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Given ,
- Charge (q) = 12 × (10)^5 C
- Time (t) = 10 min or 600 sec
- Resistance (r) = 80 ohm
We know that ,
Substitute the known values , we get
I = 12 × (10)^5/600
I = 1200000/600
I = 2000 amp
We know that ,
Substitute the known values , we get
V = 2000 × 80
V = 160000
V = 16 × (10)^4 volt
We know that ,
Substitute the known values , we get
Work = 16 × (10)^4 × 12 × (10)^5
Work = 192 × (10)^9 joule
Hence , the required values of current , potential difference and work are 2000 amp , 16 × (10)^4 volt and 192 × (10)^9 joule
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