Question

a charge of 12*10 to the power 5 flows in a conductor for 10 minutes.if the resistance offered by the conductor is 80ohm calculate the
A.current flowing
B.voltate
C.work

Answer 1

$\underline{ \mathfrak{\huge{\boxed{\fcolorbox{purple}{orange}{\purple{Answer\::-}}}}}} \\ \\ \star \rm \: \red{given} \begin{cases} \dagger \rm\: q = 12 \times {10}^{5} \: C \\ \dagger\rm \: t = 10 \: min \\ \dagger \rm \: R = 80 \Omega\end{cases} \\ \\ \star \rm \: \red{To \: Find} \begin{cases} \dagger \rm \: current \: flowing \\ \dagger \rm \: voltage \\ \dagger \rm \: work \: done\end{cases} \\ \\ \star \rm \: \red{Formula} \begin{cases} \dagger \: \boxed{ \rm{ \pink{ \bold{I = \frac{q}{t}}}}} \\ \\ \dagger \: \boxed{ \rm{ \bold{ \purple{V = IR}}}} \\ \\ \dagger \: \boxed{ \rm{ \bold{ \orange{W = qV}}}} \end{cases} \\ \\ \star \rm \: \red{Calculation} \\ \\ \implies \rm \: for \: current \\ \\ \leadsto \rm \: I = \frac{q}{t} = \frac{12 \times {10}^{5} }{600} = 2000 \: A \\ \\ \implies \rm \: for \: voltage \\ \\ \leadsto \rm \: V = IR = 2000 \times 80 = 16 \times {10}^{4} \: volt \\ \\ \implies \rm \: for \: work \\ \\ \leadsto \rm \: W = qV = 12 \times {10}^{5} \times 16 \times {10}^{4} = 1.92 \times {10}^{11} \: J \\ \\ \star \rm \: \red{Final \: Ans} \begin{cases} \dagger \: \boxed{ \rm{ \pink{I = 2000 \: A}}} \\ \\ \dagger \: \boxed{ \rm{ \purple{V = 1.6 \times {10}^{5} \: volt }}}\\ \\ \dagger \: \boxed{ \rm{ \green{W = 1.92 \times {10}^{11} \: J}}}\end{cases}$

Answer 2

$\huge \fcolorbox{red}{pink}{Solution :)}$

Given ,

• Charge (q) = 12 × (10)^5 C
• Time (t) = 10 min or 600 sec
• Resistance (r) = 80 ohm

We know that ,

$\sf \large \fbox{ \fbox{Current = \frac{Charge}{Time} }}$

Substitute the known values , we get

I = 12 × (10)^5/600

I = 1200000/600

I = 2000 amp

We know that ,

$\sf \large \fbox{ \fbox{Potential \: difference = Current \times Resistance }}$

Substitute the known values , we get

V = 2000 × 80

V = 160000

V = 16 × (10)^4 volt

We know that ,

$\sf \fbox{ \large \fbox{Work = Potential \: difference × Charge }}$

Substitute the known values , we get

Work = 16 × (10)^4 × 12 × (10)^5

Work = 192 × (10)^9 joule

Hence , the required values of current , potential difference and work are 2000 amp , 16 × (10)^4 volt and 192 × (10)^9 joule

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