Question

A charge of 12 C is moved from one point A to another point B. The potential difference between A and B is 15 V. Find the work done to move the charge.

Answer 1

Need to FinD :-

• The work done to move the charge .

$\red{\frak{Given}}\begin{cases}\textsf{ A charge of 12C is moved from A to B .}\\\textsf{ The potential difference between A and B is 15V .}\end{cases}$

We know that the Potential difference is defined as the work done in moving a unit positive charge from infinity to a certain point in an electric field . So that ,

$\twoheadrightarrow\boxed{\red{\sf Voltage = \dfrac{Work}{Charge} }}$

• Now put on the respective values .

$\sf\dashrightarrow Voltage = \dfrac{Work}{Charge} \\\\\sf\dashrightarrow 15V = \dfrac{Work}{15C}\\\\\sf\dashrightarrow Work = (15V)(15C) \\\\\sf\dashrightarrow \boxed{\pink{\frak{ Work = 225 \ Joules }}}$

Hence the work done is 225 Joules .

Answer 2

Given :-

• A charge of 12 c is moved from A to B

• The potential difference between A and B is 15 V

To Find :-

• The work done to move the charge

Solution :-

~We know that

☞ The potential difference is defined as the work done in moving a unit positive charge from infinity to a certain point in an electric field.

~So That :-

Voltage = Work/Charge

• Putting the values :

➜ Voltage = Work/Charge

➜ 15 V = Work/12 C

➜ Work = 15 V × 12 C

➜ Work = 180 joules.

Hence, The work done is 180 joules.