Question

A charge of 120C is brought from a potential of 600V to a point 'P' by doing work of 150 joules. Find the potential of point P​

Answer 1

Answer:

598.75V

Explanation:

Here, Q = 120C

W = 150J

Potential diff. at higher point = 600V

Let the p.d at the lower point be p.

Then, V = 600-p

Thus, V = W/Q = 150/120 = 5/4

-p = 5/4 - 600 = -598.75

Or, p = 598.75 V