Question

A charge of 12C is moved from point A to point B, having potentials 10V and 50V respectively. What is the energy acquired by the charge​

Answer 1

Explanation:

We know that potential difference = Work done/Charge moved.

In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.

Thus, the potential difference = v2-V1 = 230-240 = 10 V

Therefore, Work done = Potential difference * Charge moved.

That is, 10 * 5 = 50 Joules.

Hence, the work done in moving a charge of 5 coulombs from a point at 230 volts to another point at 240 volts is 50 J.