Question

A charge of 1500um is distributed uniformly over a very large sheet of surface 300m^2. Calculate the electric field at a distance of 25cm.

Answer 1

Answer:

2.82 × 10^5NC^-1

Explanation:

surface charge density of the sheet

S = q/A

S = 1500×10^-6C / 300m^2

S = 5×10^-6 Cm^-2

Electric field at a distance of 20cm from it in air,

E = S/2Eo

E = 5×10^-6 / 2×8.85×10^12

E = 2.82×10^5 NC^-1