Question

A charge of 16 PC is accelerated through a potential difference of 100V, it K.E. will be (a) 10 ev (b)1010 ev (0) 10-10 ev (d) 10'ev

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Answer 1

Answer:-

• Charge=Q=16PC
• Potential difference=V=100V

We know

$\boxed{\sf E_K=VQ}$

$\\ \sf\longmapsto E_K=100\times 16$

$\\ \sf\longmapsto E_K=1600$

$\\ \sf\longmapsto E_K=10'eV$

Answer 2

Answer:

10ev his ksndoo skanaksnjdosnksna