Question

A charge of 2 x10-6 C moves across two points having a potential difference of 10 volt. What is the amount of work done?

Answer 1

Answer:

given,

charge (Q) = 2 × 10-6 C

Potential Difference (V) = 10 V

we know that,

potential difference is the work done to move a particular charge between any two points in a conductor.

so,

V=W/Q

=> 10 = W / 2× 10-6

=> 10 × 2 × 10-6 = W

=> W = 20×10-6 J

Answer 2

Answer:

$\bold {2 \times {10}^{ - 5} Joules = Work \: done}$

Explanation:

We know that,

V = W/Q

Where,

Q = charge = 2 x10-6 C

W = work done = ?

Volt = 10V

$10 = \frac{W}{2 \times {10}^{ - 6} }$

$10 \times 2 \times {10}^{ - 6 } = W$

$20 \times {10}^{ - 6} = W$

$W = 2 \times {10}^{ - 5} Joules$